Duplicate Counts per column

I'm have a problem with trying to generate a view that has a count of duplicates values per column in a table.

example I have a table with the following structure:

CREATE TABLE [dbo].[TestDpln](
[CountryCode] [smallint] NOT NULL DEFAULT ((0)),
[NPA] [smallint] NOT NULL DEFAULT ((0)),
[NXX] [smallint] NOT NULL DEFAULT ((0)),
[XXXX] [smallint] NOT NULL DEFAULT ((0)),
[3-Digit] [nvarchar](3) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[4-Digit] [nvarchar](4) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[SiteIdx] [int] NULL DEFAULT ((0)),
CONSTRAINT [TestDpln$PrimaryKey] PRIMARY KEY NONCLUSTERED
(
[CountryCode] ASC,
[NPA] ASC,
[NXX] ASC,
[XXXX] ASC
)WITH (PAD_INDEX = OFF, IGNORE_DUP_KEY = OFF) ON [PRIMARY]
) ON [PRIMARY]

the data loaded looks like this

INSERT INTO dbo.TestDpln VALUES('1','312','555','1212','212','1212','1')
INSERT INTO dbo.TestDpln VALUES('1','312','555','1213','213','1213','1')
INSERT INTO dbo.TestDpln VALUES('1','525','555','2212','212','2212','2')
INSERT INTO dbo.TestDpln VALUES('1','525','555','2213','213','2213','2')

the results I need are

SiteIdx 3 Digit Count 4 Digit Count
--- ---- ----
1 2 0
2 2 0

I've tried various queries the closest being:

SELECT DISTINCT SiteIdx, COUNT(*) as "3-Digit Count"
FROM dbo.TestDpln
GROUP BY SiteIdx, "3-Digit"
HAVING COUNT(*) > 1

but it only shows one column and one site I'm not sure how to get the '4 Digit Count' column to show up and the rest of the sites. below are the results I get so far.

SiteIdx 3 Digit Count
--- ----
1 2

any help would be great.
Thanks
MikeTry:
COUNT(DISTINCT [YourColumn])|||That did not work I was thinking it would need to be some sort of select statement run on each column then grouped by the siteidx then a count done by site. I'm just not sure how to write it.|||Your data and required output doesn't agree
3d 4d idx
INSERT INTO dbo.TestDpln VALUES('1','312','555','1212','212','1212','1')
INSERT INTO dbo.TestDpln VALUES('1','312','555','1213','213','1213','1')
No duplicates here but you want 2 0 1

INSERT INTO dbo.TestDpln VALUES('1','525','555','2212','212','2212','2')
INSERT INTO dbo.TestDpln VALUES('1','525','555','2213','213','2213','2')
and no duplicates here but you want 2 0 2
And then you also ask how to display the rest of the sites
So do you want all zeros returned if a siteidx has no duplicates?|||How do you expect to get 4-Digit counts of zero from the data you supplied, which obviously contains multiple 4-Digit count values?|||Sorry for being so unclear it was a long day and not enough coffee

First the piece that I forgot to put in is that there is an input string that we pass in and are searching for such as '51212' this string is then broken down in to 3 digits from the right giving the search string for the 3 digit column of 212 and then four digits from the right giving the search string for the four digit column of 1212

so with this information and some updated data this is what I'm looking for

Input string 51212
3d 4d Site
INSERT INTO dbo.TestDpln VALUES('1','312','555','1212','212','1212','1')
INSERT INTO dbo.TestDpln VALUES('1','312','555','1213','213','1213','1')
INSERT INTO dbo.TestDpln VALUES('1','312','533','1212','212','1212','1')
INSERT INTO dbo.TestDpln VALUES('1','312','533','1213','213','1213','1')
INSERT INTO dbo.TestDpln VALUES('1','312','577','2212','212','2212','1')
INSERT INTO dbo.TestDpln VALUES('1','312','577','2213','213','2213','1')
INSERT INTO dbo.TestDpln VALUES('1','525','555','2212','212','2212','2')
INSERT INTO dbo.TestDpln VALUES('1','525','555','2213','213','2213','2')
3 digit 212 duplicates would be 4
4 digit 1212 duplicates would be 2

But the final output should look like

SiteIdx 3digit 4digit
--- -- --
1 4 2|||I hope this example is better|||You sure pick some bad column names.
set nocount on
CREATE TABLE [dbo].[TestDpln](
[CountryCode] [smallint] NOT NULL DEFAULT ((0)),
[NPA] [smallint] NOT NULL DEFAULT ((0)),
[NXX] [smallint] NOT NULL DEFAULT ((0)),
[XXXX] [smallint] NOT NULL DEFAULT ((0)),
[3-Digit] [nvarchar](3) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[4-Digit] [nvarchar](4) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[SiteIdx] [int] NULL DEFAULT ((0)),
CONSTRAINT [TestDpln$PrimaryKey] PRIMARY KEY NONCLUSTERED
(
[CountryCode] ASC,
[NPA] ASC,
[NXX] ASC,
[XXXX] ASC
))

INSERT INTO dbo.TestDpln VALUES('1','312','555','1212','212','1212','1')
INSERT INTO dbo.TestDpln VALUES('1','312','555','1213','213','1213','1')
INSERT INTO dbo.TestDpln VALUES('1','312','533','1212','212','1212','1')
INSERT INTO dbo.TestDpln VALUES('1','312','533','1213','213','1213','1')
INSERT INTO dbo.TestDpln VALUES('1','312','577','2212','212','2212','1')
INSERT INTO dbo.TestDpln VALUES('1','312','577','2213','213','2213','1')
INSERT INTO dbo.TestDpln VALUES('1','525','555','2212','212','2212','2')
INSERT INTO dbo.TestDpln VALUES('1','525','555','2213','213','2213','2')

declare @.InputString char(5)
set @.InputString = '51212'

select SiteIDx,
sum(case when [3-Digit] = right(@.InputString, 3) then 1 else 0 end) as '3digit',
sum(case when [4-Digit] = right(@.InputString, 4) then 1 else 0 end) as '4digit'
from [dbo].[TestDpln]
group by SiteIDx

drop table [dbo].[TestDpln]|||That worked great a million thanks to you I never would have thought about using sum for this.
P.S.
I know the column names are bad I inherited this from someone who was trying to use MSACCESS for this data and now I need to really make it work on MSSQL we are redoing the whole schema as we build this.